Updated On 195 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now! Best Answer Suppose that we have an equation y=ax^2bxc whose graph is a parabola with vertex (3,2), vertical axis of symmetry, and contains the point (1,0)Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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What does b represent in ax^2+bx+c
What does b represent in ax^2+bx+c-You get these gems as you gain rep from other members for making good contributions and giving helpful advice #2 Report 6 years ago #2 ( Original post by differentiation) y=x^3ax^2bxc, where the curve touches the xaxis at x = 3 and x = 1Click here👆to get an answer to your question ️ The diagram shows the graph of y = ax^2 bx c , then Join / Login maths The diagram shows the graph of y = a x 2 b x c, then




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Y ax 2 bx c x b b 2 4 ac2 a x b b 2 4 ac2 a this y = ax 2 bx c = x b √ b 2 4 ac 2 a x b √ b 2 4 ac 2 a This works with everything, although sometimes the root is complex ( C ) There are other ways Example 33 1Click here👆to get an answer to your question ️ The vertex of the parabola y = ax^2 bx c is Join / Login maths The vertex of the parabola y = a x 2 b x c is Answer y = a x 2 b x c The vertex will correspond to the point where the curve attains a minima (a > 0) or maxima (a < 0)Given and Also ⇒ We know that ⇒ Hence;
B is the coefficient of the y term c is the constant term the slopeintercept form of the equation of a straight line is y = mx b where m is the slope b is the yintercept to convert from the standard form of the equation of a straight line to the slopeintercept form of the equation for a straight line, solve for x ax by = c is the standard form subtract ax from both sides of thisGiven y = ax 2 bx c , we have to go through the following steps to find the points and shape of any parabola Label a, b, and c Decide the direction of the paraola If a > 0 (positive) then the parabola opens upward If a < 0 (negative) then the parabolaF"(a), f"(b), f"(c) are Given f(x) = ax 2 bx c ⇒ ⇒ So f"(a)= f"(b;
Y = ax 2 bx c In this exercise, we will be exploring parabolic graphs of the form y = ax 2 bx c, where a, b, and c are rational numbers In particular, we will examine what happens to the graph as we fix 2 of the values for a, b, or c, and vary the third We have split it up into three parts varying a only varying b only varying c onlyIn this case, a = 2, b = –4, and c = –3 Then the answer is x = –058, x = 258 , rounded to two decimal places Warning The "solution" or "roots" or "zeroes" of a quadratic are usually required to be in the "exact" form of the answer y = ax 2 bx c is a parabola In the following applet, you can explore what the a, b, and c variables do to the parabolic curve The effects of variables a and c are quite straightforward, but what does variable b do?



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Solution for ax^2bx=cy equation Simplifying ax 2 bx = c 1y Solving ax 2 bx = c 1y Solving for variable 'a' Move all terms containing a to the left, all other terms to the right Add '1bx' to each side of the equation ax 2 bx 1bx = c 1bx 1y Combine like terms bx 1bx = 0 ax 2 0 = c 1bx 1y ax 2 = c 1bx 1y Reorder the terms ax 2 = 1bx c 1y Divide If the polynomial `x^(3)ax^(2)bx30` is exactly divisible by `x^(2)2x15` Find a and b and also the third factor asked in Mathematics by Eshaan01 ( 714k points)Watch Video in App This browser does not support the video element



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For more problems and solutions visit http//wwwmathplanetcom√1000以上 y=ax2 bx c equation What does y=ax2bxc mean Quadratic Formula Calculator What does y=ax2bxc mean What does y=ax2bxc meanGraphing A Parabola Of The Form Y Ax 2 Bx C Integer Coefficients Youtube How to Find the Axis ofSymmetry y = ax2 bx c The line for the axis of symmetry crosses over the number achieved by doing the formula –b/2a 9 Problem 1 Formula y = ax2 bx c y = 5x2 10x – 3 Directions find the vertex, yintercept



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3 The curve y =ax 2 bx c passes through the point (2, 4) and is tangent to the line y = x 1 at (0, 1) Determine values for a, b, and c Gauss sits at the point (b –c, 4a)If then which one of the following is correct? If y=ax^(2)bxc passes through the points (3, 10), (0, 1), and (2, 15) , what is the value of abc ?



Assignment 2 By Shridevi Kotta This Write Up Explores Equation Of Parabola Y Ax2 Bx C We Observe That With B C 0 A Determines How The Parabola Is Oriented And The Curve Rises Fast Or Slow In Other Words How Narrow Or How Wide The Parabola Is At




View Question What Do A B And C Mean In Y Ax 2 Bx C
Answer provided by our tutors y= ax^2 bx c a) touches the xaxis at 4 and passes through (2,12) touches the xaxis at 4 means that passes trough (4,0) and b^2 4*a*c = 0 (the quadratic has 1 solution) passes trough (4,0) that is for x=4 y=0 4 = a*0^2 b*0 c c = 4 passes through (2,12) that is x = 2 and y = 12Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreThings to Do In this applet, you start with a simple quadratic curve (a parabola) You can investigate the curve as follows




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(1) a constant (2) a function of x only (3) a function of y only (4) a function of x and y Solution Given y 2 = ax 2 bx c Differentiate wrtx 2y dy/dx = 2ax b (i)I have this equation y = *x^*x And I would like to obtain the result of the equation when I give "y" numbers, edited explanation 2/06/ I want toA compound quadratic is a polynomial that can be expressed in the form a x 2 n b x n c ax^{2n}bx^{n}c a x 2 n b x n c, where a ≠ 0, b a \neq 0,b a = 0, b and c c c are constants, and n n n is a positive integer This can be generalized to compound polynomials, where the degree of the terms is a multiple of some positive integer



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5) The xcoordinate of the vertex is at b/2a The ycoordinate of this vertex is found by plugging in x = b/2a into ax^2 bx c Those aren't really handy for graphing, however What you do in practice if you want to graph ax^2 bx c is you complete the square You get it in the form a(xh)^2 y = ax² bx c y bx c = ax² x² x²(y/x²) (b/x) (c/x²) = a john1231 john1231 Mathematics High School answered Y = ax^2bxc, solve for a 1 See answer john1231 is waiting for your help Add your answer and earn points f(x)=ax^2bxc => f'(x)=2axb Remember that the derivative of a sum is the sum of the derivatives (y(x)g(x)z(x))'=y'(x)g'(x)z'(x) In this case f(x)=y(x)g(x)z(x



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The equation of a curve is y = x^2 ax b where a and b are integers The points (0,5) and (5,0) lie on the curve Find the coordinates of the turning point of the curve In the equation for our line we have 2 unknowns a and bF'(a), f'(b), r(c) are in Given f(x) = ax 2 bx c ⇒ But b= 0 So I;Since ⇒ ⇒ = ⇒ ⇒ We kno



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The curve {eq}y = ax^2 bx c {/eq} passes through the point {eq}(1,6) {/eq} and is tangent to the line {eq}y = 4x {/eq} at the origin Find {eq}a, b, {/eq} and {eqConverting $y=ax^2bxc$ to $y=a(xh)^2k$ A quadratic equation in the form $\cl"red"{y=ax^2bxc}$ is said to be in standard form, while an equation in the form $\cl"blue"{y=a(xh)^2k}$ is said to be in vertex form In this section you will learn to convert equations such as $y=2x^22x3$ from standard form to vertex form A quadratic function is a function of the form y = ax 2 bx c, where a≠ 0, and a, b, and c are real numbers How does b affect the parabola?




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y = ax^2 bx c is a quadratic equation The vertex is located at (2, 5) and the graph opens up, this means that it never intercepts the x The second equation will come from taking the derivative of your original function \begin{align*} y &= ax^2 bx c \\ \frac{dy}{dx} &= 2ax b \end{align*} We know that since the relative max occurs at $(3,12)$ we know that $\frac{dy}{dx} = 0$ and $x = 3$ so plugging in we have $$ 0 = 6a b $$ So that results in our two equations being \begin{align*} 11 &= 9a 3b \\ 0 &= 6a bOf that vague equation, the X coordinate is at b/2a To find the Y coordinate, plug it back in Now if you would like to do this the calculus way, differentiate the equation, and set the resulting 2ax = b and solve for X Then, plug the X back




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In the next few questions, we will find the roots of the general equation y = a x 2 b x with a ≠ 0 by factoring, and use that to get a formula for the axis of symmetry of any equation in that form Question 5 We want to factor a x 2 b x Because both terms contain an x, Stack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack ExchangeRewrite the equation as ax2 bx c = y a x 2 b x c = y Move y y to the left side of the equation by subtracting it from both sides Use the quadratic formula to find the solutions Substitute the values a = a a = a, b = b b = b, and c = c−y c = c y into the quadratic formula and solve for x x Simplify the numerator



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We will learn how to find the maximum and minimum values of the quadratic Expression ax^2 bx c (a ≠ 0) When we find the maximum value and the minimum value of ax^2 bx c then let us assume y = ax^2 bx c Or, ax^2 bx c y = 0 Suppose x is real then the discriminant of equation ax^2 bx c y = 0 is ≥ 0 ie, b^2 4a(cWhen b = 0, the vertex of the parabola lies on the yaxis Changing b does not affect the shape of the parabola (as changing a did) Making b positive or negative only reflects the parabola across the yExplain Let us write the equation ax by = c in slope intercept form y = (a/b)x c/b The slope is given by (a/b) Set a, b and c to some values Drag the red markers so that they are on the line, read their coordinates and find the slope of the line Compare the slope found to (a/b)




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Graphing Y Ax 2 Bx C
22 Y=A(1B^X) Power 23 Y=AX^(BX^C) Power^Power 24 Y=A(EXP(BX))C(EXP(DX)) Sum of Exponentials 25 Y=A(X^B)EXP(CX) Exponential Type 1 26 Y=(ABX)EXP(CX)D Exponential Type 2 27 Y=AB(EXP(C(XD)^2)) Normal 28 Y=A(B/X)EXP(C(LN(X)D)^2) Lognormal 29 Y=A Exp(BX) Exponential Y=ax^2bxc a 0Lv 7 1 decade ago IF small and large case letters have the same meaning within this queston then 1) "Y"or "y" represents the vertical axis value of a position/displacement vs time relationship The displacement of this motion has a parabolic graph shapeIf Y = Ax^2 Bx C is the position of the car the velocity is the derivative of this equation theThe Graph of y = ax2 bx c 393 Lesson 64 The Graph of y = ax2 bx c Lesson 6–4 2 BIG IDEA The graph of y = ax bx c, a ≠ 0, is a parabola that opens upward if a > 0 and downward if a < 0 Standard Form for the Equation of a Parabola Homer King hits a high–fl y




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Y = ax 2 bx c Move the loose number over to the other side y – c = ax 2 bx Factor out whatever is multiplied on the squared term Make room on the lefthand side, and put a copy of "a" in front of this spaceIf and then what is equal to?Given a quadratic function \(f(x) = ax^2bxc\), it is described by its curve \y = ax^2bxc\ This type of curve is known as a parabola A typical parabola is shown here Parabola,




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